## Solve by using the Pythagorean Theorem. A bus leaves from campus headed east at 35 miles per hour and another bus leaves from campus h

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## Answers ( No )

The relationship of distance-speed-timedistance = velocity × time

d = vt

Given:v₁ = 35 mph

v₂ = 50 mph

the hypotenuse = 366

for example h is the time in hour

Solution:d₁² + d₂² = (hypotenuse)²

(v₁t)² + (v₂t)² = 366²

(35h)² + (50h)² = 366²

1,225h² + 2,500h² = 133,956

3,725h² = 133,956

h² = 133,956 / 3,725

h² = 35.9613

h = 5.99

to the nearest hour ⇒ 6

The buses will be 366 miles apart in 6 hours